IPL 2019 final: Mumbai Indians win toss, elect to bat against CSK

Both teams have won three IPL titles each

PTI5_7_2019_000177B [File] CSK skipper M.S. Dhoni watches his MI counterpart Rohit Sharma toss the coin during the First Qualifier of Indian Premier League 2019 (IPL T20) playoffs cricket match | PTI

Mumbai Indians won the toss and chose to bat first against Chennai Super Kings in the final of the Indian Premier League 2019, at the Rajiv Gandhi International Cricket Stadium in Hyderabad.

MI skipper Rohit Sharma said only one has been made to their playing XI—Mitchell McClenaghan comes in for Jayant Yadav. There were no changes to Mahendra Singh Dhoni-led CSK.

Both teams have won three IPL titles each. Mumbai Indians, though, have a slightly upper hand, having beaten CSK thrice this season.

Teams

Mumbai Indians:

Quinton de Kock (wk), Rohit Sharma (C), Suryakumar Yadav, Ishan Kishan, Hardik Pandya, Krunal Pandya, Kieron Pollard, Mitchell McClenaghan, Rahul Chahar, Lasith Malinga, Jasprit Bumrah

Chennai Super Kings:

Shane Watson, Faf du Plessis, Suresh Raina, Ambati Rayudu, M.S. Dhoni (C and wk), Dwayne Bravo, Ravindra Jadeja, Deepak Chahar, Harbhajan Singh, Imran Tahir, Shardul Thakur

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