Powered by

Williamson wins toss, opts to bowl against India in first ODI

India have handed debuts to Arshdeep Singh and Umran Malik

PTI11_24_2022_RPT062B Indian captain Shikhar Dhawan and New Zealand skipper Kane Williamson with the ODI series trophy ahead of the matches, at Eden Park, Auckland, New Zealand, Thursday, Nov. 24, 2022 | PTI

New Zealand skipper Kane Williamson won the toss and elected to bowl against India in the first One-Day International, in Auckland on Friday.

India have handed debuts to Arshdeep Singh and Umran Malik and are fielding both Rishabh Pant and Sanju Samson.

The visitors are playing with three specialist fast bowlers while the hosts are going in with four of them. 

Williamson had missed the final match of the T20I series due to a medical appointment but is back to lead the side.

India had won the three-match T20 series 1-0.

Teams:

India: Shikhar Dhawan (C), Shubman Gill, Rishabh Pant, 4 Shreyas Iyer, Suryakumar Yadav, Sanju Samson, Washington Sundar, Shardul Thakur, Umran Malik, Arshdeep Singh and Yuzvendra Chahal.

New Zealand: Kane Williamson (C), Finn Allen, Devon Conway,  Tom Latham, Daryl Mitchell, Glenn Phillips, Mitchell Santner, Adam Milne, Matt Henry, Tim Southee and Lockie Ferguson. PTI AT   AT AT 11250644

📣 The Week is now on Telegram. Click here to join our channel (@TheWeekmagazine) and stay updated with the latest headlines